The phosphorous-to-hydrogen mass ratio is 10.2 for a compound. Login to reply the answers Post; pelzer. 4 years ago. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride. asked by Trudy on February 27, 2011; physics. 14. Copper (II) fluoride contains 37.42%by mass. Solution for Copper(II) fluoride contains 37.42% F by mass. Login to reply the answers Post; molano. How many total atoms are in the formula Al2(CO3)3? Molar volume: 24.005 cm³/mol. Calculate the mass of fluorine(in grams)contained in 55.5 g of Copper(II) Fluoride.
Lv 4. Molecular formula: CuF 2. There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.
A piece of copper ball of mass 20g at 200°c is placed in a copper calorimeter of mass 60g containing 50g of water at 30°c ignoring heat losses.calculate the final steady temperature of mixture. 1 kg: $685.00 5 kg: $3,160.00 For other quantities or purities not listed, please request a quotation. 37.42 % F by mass means 100 g of copper (II) fluoride contains 37.42 g of F. So, 100 g of copper (II) fluoride contains 37.42 g of F because the mass of copper fluoride has no units .. it could be 56.0 mg, g. or kg or perhaps something else. I'll assume it is 56g . Copper (II) Fluoride: Synonyms: Cupric fluoride, cupric difluoride: Formula: CuF2: Purity: 99.5%: CAS Number: 7789-19-7: Molecular Weight: 101.54: Color & Form: White-gray powder: Boiling Point: 950° C: Specific Gravity: 4.85 gm/ml: Solubility: Soluble: Options. How many of each type of atoms are there in the formula NH4C2H3O2? The formula for Copper (II) Fluoride is CuF2, which is broken down to 63.55(Cu), and 37.98 (for 2 F) So the correct answer is: 63.55+37.98=101.53, so the answer is A (difference of .03 would be due to rounding differences). Copper Ii Fluoride. 0 5 0. This WebElements periodic table page contains copper fluoride for the element copper Source(s): retired chem examiner. CAS Registry Number (CAS RN): 7789-19-7. Explanation: x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen. Why?.. Source(s): https://shrink.im/a84F4. This ratio could correspond to the compound _____? Elements: Copper (Cu), Fluorine (F) Molecular weight: 101.543 g/mol. 0 0 1. PH3. Law of Constant Composition .
The oxygen-to-hydrogen mass ratio of water is always 8.0 is an example of what fundamental law?
Mass of fluorine = 56 x 37.42/100 = 20.956g.